X^2+y/1.2=10+y/1.2

Solution for X^2+y/1.2=10+y/1.2 equation:

X^2+X/1.2=10+X/1.2

We move all terms to the left:

X^2+X/1.2-(10+X/1.2)=0

We add all the numbers together, and all the variables

X^2+X/1.2-(X/1.2+10)=0

We get rid of parentheses

X^2+X/1.2-X/1.2-10=0

We multiply all the terms by the denominator


X^2*1.2+X-X-10*1.2=0

We add all the numbers together, and all the variables

X^2*1.2-12=0

Wy multiply elements

1.2X^2-12=0

a = 1.2; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·1.2·(-12)
Δ = 57.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{57.6}}{2*1.2}=\frac{0-\sqrt{57.6}}{2.4}
=-\frac{\sqrt{}}{2.4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{57.6}}{2*1.2}=\frac{0+\sqrt{57.6}}{2.4}
=\frac{\sqrt{}}{2.4}
$